10c^2-29c+21=0

Solution for 10c^2-29c+21=0 equation:

Simplifying
10c2 + -29c + 21 = 0

Reorder the terms:
21 + -29c + 10c2 = 0

Solving
21 + -29c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(7 + -5c)(3 + -2c) = 0

Subproblem 1
Set the factor '(7 + -5c)' equal to zero and attempt to solve:

Simplifying
7 + -5c = 0

Solving
7 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -5c = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -5c = 0 + -7
-5c = 0 + -7

Combine like terms: 0 + -7 = -7
-5c = -7

Divide each side by '-5'.
c = 1.4

Simplifying
c = 1.4
Subproblem 2
Set the factor '(3 + -2c)' equal to zero and attempt to solve:

Simplifying
3 + -2c = 0

Solving
3 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2c = 0 + -3
-2c = 0 + -3

Combine like terms: 0 + -3 = -3
-2c = -3

Divide each side by '-2'.
c = 1.5

Simplifying
c = 1.5
Solution
c = {1.4, 1.5}